(2x+3)=(3x-28)

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Solution for (2x+3)=(3x-28) equation: 



(2x+3)=(3x-28)

We move all terms to the left:

(2x+3)-((3x-28))=0

We get rid of parentheses

2x-((3x-28))+3=0



We calculate terms in parentheses: -((3x-28)), so:

(3x-28)

We get rid of parentheses

3x-28

Back to the equation:

-(3x-28)



We get rid of parentheses

2x-3x+28+3=0

We add all the numbers together, and all the variables

-1x+31=0

We move all terms containing x to the left, all other terms to the right

-x=-31

x=-31/-1

x=+31

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