(2x+3)=(4x+20)

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Solution for (2x+3)=(4x+20) equation: 



(2x+3)=(4x+20)

We move all terms to the left:

(2x+3)-((4x+20))=0

We get rid of parentheses

2x-((4x+20))+3=0



We calculate terms in parentheses: -((4x+20)), so:

(4x+20)

We get rid of parentheses

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

2x-4x-20+3=0

We add all the numbers together, and all the variables

-2x-17=0

We move all terms containing x to the left, all other terms to the right

-2x=17

x=17/-2

x=-8+1/2

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