(2x+3)=(x+20)

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Solution for (2x+3)=(x+20) equation: 



(2x+3)=(x+20)

We move all terms to the left:

(2x+3)-((x+20))=0

We get rid of parentheses

2x-((x+20))+3=0



We calculate terms in parentheses: -((x+20)), so:

(x+20)

We get rid of parentheses

x+20

Back to the equation:

-(x+20)



We get rid of parentheses

2x-x-20+3=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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