(2x+3)=+(9x-3)=

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Solution for (2x+3)=+(9x-3)= equation:



(2x+3)=+(9x-3)=
We move all terms to the left:
(2x+3)-(+(9x-3))=0
We get rid of parentheses
2x-(+(9x-3))+3=0
We calculate terms in parentheses: -(+(9x-3)), so:
+(9x-3)
determiningTheFunctionDomain (9x-3)
We get rid of parentheses
9x-3
Back to the equation:
-(9x-3)
We get rid of parentheses
2x-9x+3+3=0
We add all the numbers together, and all the variables
-7x+6=0
We move all terms containing x to the left, all other terms to the right
-7x=-6
x=-6/-7
x=6/7

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