(2x+3/2)+(x-1/5)=(3x+4/10)

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Solution for (2x+3/2)+(x-1/5)=(3x+4/10) equation: 


x in (-oo:+oo)

2*x+x+3/2-(1/5) = 3*x+4/10 // - 3*x+4/10

2*x+x-(3*x)+3/2-(1/5)-(4/10) = 0

2*x+x-3*x+3/2-1/5-2/5 = 0

9/10 = 0

x belongs to the empty set

x belongs to the empty set

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