(2x+30)(2x+20)-600=336

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Solution for (2x+30)(2x+20)-600=336 equation:



(2x+30)(2x+20)-600=336
We move all terms to the left:
(2x+30)(2x+20)-600-(336)=0
We add all the numbers together, and all the variables
(2x+30)(2x+20)-936=0
We multiply parentheses ..
(+4x^2+40x+60x+600)-936=0
We get rid of parentheses
4x^2+40x+60x+600-936=0
We add all the numbers together, and all the variables
4x^2+100x-336=0
a = 4; b = 100; c = -336;
Δ = b2-4ac
Δ = 1002-4·4·(-336)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-124}{2*4}=\frac{-224}{8} =-28 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+124}{2*4}=\frac{24}{8} =3 $

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