(2x+30)(2x+26)=1596

Solution for (2x+30)(2x+26)=1596 equation:

(2x+30)(2x+26)=1596

We move all terms to the left:

(2x+30)(2x+26)-(1596)=0

We multiply parentheses ..

(+4x^2+52x+60x+780)-1596=0

We get rid of parentheses

4x^2+52x+60x+780-1596=0

We add all the numbers together, and all the variables

4x^2+112x-816=0

a = 4; b = 112; c = -816;
Δ = b2-4ac
Δ = 1122-4·4·(-816)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-160}{2*4}=\frac{-272}{8}
=-34
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+160}{2*4}=\frac{48}{8}
=6
$