(2x+30)+(3x+60)+(42-x)=180

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Solution for (2x+30)+(3x+60)+(42-x)=180 equation: 



(2x+30)+(3x+60)+(42-x)=180

We move all terms to the left:

(2x+30)+(3x+60)+(42-x)-(180)=0

We add all the numbers together, and all the variables

(2x+30)+(3x+60)+(-1x+42)-180=0

We get rid of parentheses

2x+3x-1x+30+60+42-180=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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