(2x+32)=(3x-5)

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Solution for (2x+32)=(3x-5) equation: 



(2x+32)=(3x-5)

We move all terms to the left:

(2x+32)-((3x-5))=0

We get rid of parentheses

2x-((3x-5))+32=0



We calculate terms in parentheses: -((3x-5)), so:

(3x-5)

We get rid of parentheses

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

2x-3x+5+32=0

We add all the numbers together, and all the variables

-1x+37=0

We move all terms containing x to the left, all other terms to the right

-x=-37

x=-37/-1

x=+37

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