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(2x+32/5)+(5x-4/5)=0
We add all the numbers together, and all the variables
(+2x+32/5)+(+5x-4/5)=0
We get rid of parentheses
2x+5x+32/5-4/5=0
We multiply all the terms by the denominator
2x*5+5x*5+32-4=0
We add all the numbers together, and all the variables
2x*5+5x*5+28=0
Wy multiply elements
10x+25x+28=0
We add all the numbers together, and all the variables
35x+28=0
We move all terms containing x to the left, all other terms to the right
35x=-28
x=-28/35
x=-4/5
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