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(2x+32/5)+(5x-4/5)=7x+23/5
We move all terms to the left:
(2x+32/5)+(5x-4/5)-(7x+23/5)=0
We add all the numbers together, and all the variables
(+2x+32/5)+(+5x-4/5)-(+7x+23/5)=0
We get rid of parentheses
2x+5x-7x+32/5-4/5-23/5=0
We multiply all the terms by the denominator
2x*5+5x*5-7x*5+32-4-23=0
We add all the numbers together, and all the variables
2x*5+5x*5-7x*5+5=0
Wy multiply elements
10x+25x-35x+5=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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