(2x+35)(2x+18)=1260

Solution for (2x+35)(2x+18)=1260 equation:

(2x+35)(2x+18)=1260

We move all terms to the left:

(2x+35)(2x+18)-(1260)=0

We multiply parentheses ..

(+4x^2+36x+70x+630)-1260=0

We get rid of parentheses

4x^2+36x+70x+630-1260=0

We add all the numbers together, and all the variables

4x^2+106x-630=0

a = 4; b = 106; c = -630;
Δ = b2-4ac
Δ = 1062-4·4·(-630)
Δ = 21316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21316}=146$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(106)-146}{2*4}=\frac{-252}{8}
=-31+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(106)+146}{2*4}=\frac{40}{8}
=5
$