(2x+38)=(6x-2)

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Solution for (2x+38)=(6x-2) equation: 



(2x+38)=(6x-2)

We move all terms to the left:

(2x+38)-((6x-2))=0

We get rid of parentheses

2x-((6x-2))+38=0



We calculate terms in parentheses: -((6x-2)), so:

(6x-2)

We get rid of parentheses

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

2x-6x+2+38=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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