(2x+39)=(3x+11)

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Solution for (2x+39)=(3x+11) equation: 



(2x+39)=(3x+11)

We move all terms to the left:

(2x+39)-((3x+11))=0

We get rid of parentheses

2x-((3x+11))+39=0



We calculate terms in parentheses: -((3x+11)), so:

(3x+11)

We get rid of parentheses

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

2x-3x-11+39=0

We add all the numbers together, and all the variables

-1x+28=0

We move all terms containing x to the left, all other terms to the right

-x=-28

x=-28/-1

x=+28

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