(2x+3x)/5=10

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Solution for (2x+3x)/5=10 equation: 


x in (-oo:+oo)

(2*x+3*x)/5 = 10 // - 10

(2*x+3*x)/5-10 = 0

(5*x)/5-10 = 0

(5*x)/5+(-10*5)/5 = 0

5*x-10*5 = 0

5*x-50 = 0

(5*x-50)/5 = 0

(5*x-50)/5 = 0 // * 5

5*x-50 = 0

5*x-50 = 0 // + 50

5*x = 50 // : 5

x = 50/5

x = 10

x = 10

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