(2x+4)(2x+7)=3(2x+4)

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Solution for (2x+4)(2x+7)=3(2x+4) equation: 



(2x+4)(2x+7)=3(2x+4)

We move all terms to the left:

(2x+4)(2x+7)-(3(2x+4))=0

We multiply parentheses ..

(+4x^2+14x+8x+28)-(3(2x+4))=0



We calculate terms in parentheses: -(3(2x+4)), so:

3(2x+4)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

4x^2+14x+8x-6x+28-12=0

We add all the numbers together, and all the variables

4x^2+16x+16=0

a = 4; b = 16; c = +16;
Δ = b2-4ac
Δ = 162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{8}=-2$

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