(2x+4)(2x-4)=0

Solution for (2x+4)(2x-4)=0 equation:

Simplifying
(2x + 4)(2x + -4) = 0

Reorder the terms:
(4 + 2x)(2x + -4) = 0

Reorder the terms:
(4 + 2x)(-4 + 2x) = 0

Multiply (4 + 2x) * (-4 + 2x)
(4(-4 + 2x) + 2x * (-4 + 2x)) = 0
((-4 * 4 + 2x * 4) + 2x * (-4 + 2x)) = 0
((-16 + 8x) + 2x * (-4 + 2x)) = 0
(-16 + 8x + (-4 * 2x + 2x * 2x)) = 0
(-16 + 8x + (-8x + 4x2)) = 0

Combine like terms: 8x + -8x = 0
(-16 + 0 + 4x2) = 0
(-16 + 4x2) = 0

Solving
-16 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4x2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4x2 = 0 + 16
4x2 = 0 + 16

Combine like terms: 0 + 16 = 16
4x2 = 16

Divide each side by '4'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}