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(2x+4)(3x-9)=180
We move all terms to the left:
(2x+4)(3x-9)-(180)=0
We multiply parentheses ..
(+6x^2-18x+12x-36)-180=0
We get rid of parentheses
6x^2-18x+12x-36-180=0
We add all the numbers together, and all the variables
6x^2-6x-216=0
a = 6; b = -6; c = -216;
Δ = b2-4ac
Δ = -62-4·6·(-216)
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{145}}{2*6}=\frac{6-6\sqrt{145}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{145}}{2*6}=\frac{6+6\sqrt{145}}{12} $
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