(2x+4)(4x)(x)=360

Solution for (2x+4)(4x)(x)=360 equation:

(2x+4)(4x)(x)=360

We move all terms to the left:

(2x+4)(4x)(x)-(360)=0

We multiply parentheses

8x^2+16x-360=0

a = 8; b = 16; c = -360;
Δ = b2-4ac
Δ = 162-4·8·(-360)
Δ = 11776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11776}=\sqrt{256*46}=\sqrt{256}*\sqrt{46}=16\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16\sqrt{46}}{2*8}=\frac{-16-16\sqrt{46}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16\sqrt{46}}{2*8}=\frac{-16+16\sqrt{46}}{16}
$