(2x+4)(6-2x)=0

Solution for (2x+4)(6-2x)=0 equation:

(2x+4)(6-2x)=0

We add all the numbers together, and all the variables

(2x+4)(-2x+6)=0

We multiply parentheses ..

(-4x^2+12x-8x+24)=0

We get rid of parentheses

-4x^2+12x-8x+24=0

We add all the numbers together, and all the variables

-4x^2+4x+24=0

a = -4; b = 4; c = +24;
Δ = b2-4ac
Δ = 42-4·(-4)·24
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*-4}=\frac{-24}{-8}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*-4}=\frac{16}{-8}
=-2
$