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(2x+4)(9x+11)=0
We multiply parentheses ..
(+18x^2+22x+36x+44)=0
We get rid of parentheses
18x^2+22x+36x+44=0
We add all the numbers together, and all the variables
18x^2+58x+44=0
a = 18; b = 58; c = +44;
Δ = b2-4ac
Δ = 582-4·18·44
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-14}{2*18}=\frac{-72}{36} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+14}{2*18}=\frac{-44}{36} =-1+2/9 $
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