(2x+4)(x+1)=0

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Solution for (2x+4)(x+1)=0 equation:


Simplifying
(2x + 4)(x + 1) = 0

Reorder the terms:
(4 + 2x)(x + 1) = 0

Reorder the terms:
(4 + 2x)(1 + x) = 0

Multiply (4 + 2x) * (1 + x)
(4(1 + x) + 2x * (1 + x)) = 0
((1 * 4 + x * 4) + 2x * (1 + x)) = 0
((4 + 4x) + 2x * (1 + x)) = 0
(4 + 4x + (1 * 2x + x * 2x)) = 0
(4 + 4x + (2x + 2x2)) = 0

Combine like terms: 4x + 2x = 6x
(4 + 6x + 2x2) = 0

Solving
4 + 6x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(2 + 3x + x2) = 0

Factor a trinomial.
2((2 + x)(1 + x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-2, -1}

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