(2x+4)(x-11)=0

Solution for (2x+4)(x-11)=0 equation:

(2x+4)(x-11)=0

We multiply parentheses ..

(+2x^2-22x+4x-44)=0

We get rid of parentheses

2x^2-22x+4x-44=0

We add all the numbers together, and all the variables

2x^2-18x-44=0

a = 2; b = -18; c = -44;
Δ = b2-4ac
Δ = -182-4·2·(-44)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-26}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+26}{2*2}=\frac{44}{4}
=11
$