(2x+4)+(2x+4)+(2x-4)=22

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Solution for (2x+4)+(2x+4)+(2x-4)=22 equation: 



(2x+4)+(2x+4)+(2x-4)=22

We move all terms to the left:

(2x+4)+(2x+4)+(2x-4)-(22)=0

We get rid of parentheses

2x+2x+2x+4+4-4-22=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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