(2x+4)+(x+1)=3(x-1)+6

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Solution for (2x+4)+(x+1)=3(x-1)+6 equation:


Simplifying
(2x + 4) + (x + 1) = 3(x + -1) + 6

Reorder the terms:
(4 + 2x) + (x + 1) = 3(x + -1) + 6

Remove parenthesis around (4 + 2x)
4 + 2x + (x + 1) = 3(x + -1) + 6

Reorder the terms:
4 + 2x + (1 + x) = 3(x + -1) + 6

Remove parenthesis around (1 + x)
4 + 2x + 1 + x = 3(x + -1) + 6

Reorder the terms:
4 + 1 + 2x + x = 3(x + -1) + 6

Combine like terms: 4 + 1 = 5
5 + 2x + x = 3(x + -1) + 6

Combine like terms: 2x + x = 3x
5 + 3x = 3(x + -1) + 6

Reorder the terms:
5 + 3x = 3(-1 + x) + 6
5 + 3x = (-1 * 3 + x * 3) + 6
5 + 3x = (-3 + 3x) + 6

Reorder the terms:
5 + 3x = -3 + 6 + 3x

Combine like terms: -3 + 6 = 3
5 + 3x = 3 + 3x

Add '-3x' to each side of the equation.
5 + 3x + -3x = 3 + 3x + -3x

Combine like terms: 3x + -3x = 0
5 + 0 = 3 + 3x + -3x
5 = 3 + 3x + -3x

Combine like terms: 3x + -3x = 0
5 = 3 + 0
5 = 3

Solving
5 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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