(2x+4)+(x+2)=3(x-1)+7

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Solution for (2x+4)+(x+2)=3(x-1)+7 equation: 



(2x+4)+(x+2)=3(x-1)+7

We move all terms to the left:

(2x+4)+(x+2)-(3(x-1)+7)=0

We get rid of parentheses

2x+x-(3(x-1)+7)+4+2=0



We calculate terms in parentheses: -(3(x-1)+7), so:

3(x-1)+7

We multiply parentheses

3x-3+7

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

3x-(3x+4)+6=0

We get rid of parentheses

3x-3x-4+6=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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