(2x+4)+(x+2)=3(x-1)+8

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Solution for (2x+4)+(x+2)=3(x-1)+8 equation: 


Simplifying
(2x + 4) + (x + 2) = 3(x + -1) + 8

Reorder the terms:
(4 + 2x) + (x + 2) = 3(x + -1) + 8

Remove parenthesis around (4 + 2x)
4 + 2x + (x + 2) = 3(x + -1) + 8

Reorder the terms:
4 + 2x + (2 + x) = 3(x + -1) + 8

Remove parenthesis around (2 + x)
4 + 2x + 2 + x = 3(x + -1) + 8

Reorder the terms:
4 + 2 + 2x + x = 3(x + -1) + 8

Combine like terms: 4 + 2 = 6
6 + 2x + x = 3(x + -1) + 8

Combine like terms: 2x + x = 3x
6 + 3x = 3(x + -1) + 8

Reorder the terms:
6 + 3x = 3(-1 + x) + 8
6 + 3x = (-1 * 3 + x * 3) + 8
6 + 3x = (-3 + 3x) + 8

Reorder the terms:
6 + 3x = -3 + 8 + 3x

Combine like terms: -3 + 8 = 5
6 + 3x = 5 + 3x

Add '-3x' to each side of the equation.
6 + 3x + -3x = 5 + 3x + -3x

Combine like terms: 3x + -3x = 0
6 + 0 = 5 + 3x + -3x
6 = 5 + 3x + -3x

Combine like terms: 3x + -3x = 0
6 = 5 + 0
6 = 5

Solving
6 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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