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(2x+4)+(x-1)=3(x-1)+9
We move all terms to the left:
(2x+4)+(x-1)-(3(x-1)+9)=0
We get rid of parentheses
2x+x-(3(x-1)+9)+4-1=0
We calculate terms in parentheses: -(3(x-1)+9), so:We add all the numbers together, and all the variables
3(x-1)+9
We multiply parentheses
3x-3+9
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
3x-(3x+6)+3=0
We get rid of parentheses
3x-3x-6+3=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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