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(2x+4)+x+(10-x)=50-4x
We move all terms to the left:
(2x+4)+x+(10-x)-(50-4x)=0
We add all the numbers together, and all the variables
(2x+4)+x+(-1x+10)-(-4x+50)=0
We add all the numbers together, and all the variables
x+(2x+4)+(-1x+10)-(-4x+50)=0
We get rid of parentheses
x+2x-1x+4x+4+10-50=0
We add all the numbers together, and all the variables
6x-36=0
We move all terms containing x to the left, all other terms to the right
6x=36
x=36/6
x=6
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