(2x+4)/(3x+5)=5/7

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Solution for (2x+4)/(3x+5)=5/7 equation: 



(2x+4)/(3x+5)=5/7

We move all terms to the left:

(2x+4)/(3x+5)-(5/7)=0



Domain of the equation: (3x+5)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-5

x!=-5/3

x!=-1+2/3

x∈R



We add all the numbers together, and all the variables

(2x+4)/(3x+5)-(+5/7)=0

We get rid of parentheses

(2x+4)/(3x+5)-5/7=0

We calculate fractions


(14x+28)/(21x+35)+(-15x-25)/(21x+35)=0

We multiply all the terms by the denominator


(14x+28)+(-15x-25)=0

We get rid of parentheses

14x-15x+28-25=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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