(2x+4)/(x+5)=7/(3x+2)

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Solution for (2x+4)/(x+5)=7/(3x+2) equation:


D( x )

x+5 = 0

3*x+2 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

3*x+2 = 0

3*x+2 = 0

3*x+2 = 0 // - 2

3*x = -2 // : 3

x = -2/3

x in (-oo:-5) U (-5:-2/3) U (-2/3:+oo)

(2*x+4)/(x+5) = 7/(3*x+2) // - 7/(3*x+2)

(2*x+4)/(x+5)-(7/(3*x+2)) = 0

(2*x+4)/(x+5)-7*(3*x+2)^-1 = 0

(2*x+4)/(x+5)-7/(3*x+2) = 0

((2*x+4)*(3*x+2))/((x+5)*(3*x+2))+(-7*(x+5))/((x+5)*(3*x+2)) = 0

(2*x+4)*(3*x+2)-7*(x+5) = 0

6*x^2+9*x-27 = 0

6*x^2+9*x-27 = 0

3*(2*x^2+3*x-9) = 0

2*x^2+3*x-9 = 0

DELTA = 3^2-(-9*2*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-3)/(2*2) or x = (-81^(1/2)-3)/(2*2)

x = 3/2 or x = -3

3*(x+3)*(x-3/2) = 0

(3*(x+3)*(x-3/2))/((x+5)*(3*x+2)) = 0

(3*(x+3)*(x-3/2))/((x+5)*(3*x+2)) = 0 // * (x+5)*(3*x+2)

3*(x+3)*(x-3/2) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-3/2 )

x-3/2 = 0 // + 3/2

x = 3/2

x in { -3, 3/2 }

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