(2x+4)/2-(3x/x-2)=x

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Solution for (2x+4)/2-(3x/x-2)=x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x+4)/2-((3*x)/x)+2 = x // - x

(2*x+4)/2-x-((3*x)/x)+2 = 0

(2*x+4)/2-x-3+2 = 0

(2*x+4)/2+(2*(-x))/2+(-3*2)/2+(2^2)/2 = 0

2*x+2*(-x)-3*2+4+4 = 0

4-6+4 = 0

4-2 = 0

2 = 0

2/2 = 0

2/2 = 0 // * 2

2 = 0

x belongs to the empty set

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