(2x+4)/2=(2x+5)/3

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Solution for (2x+4)/2=(2x+5)/3 equation:



(2x+4)/2=(2x+5)/3
We move all terms to the left:
(2x+4)/2-((2x+5)/3)=0
We calculate fractions
2x/()+(-((2x+5)*2)/()=0
We calculate terms in parentheses: +(-((2x+5)*2)/(), so:
-((2x+5)*2)/(
We multiply all the terms by the denominator
-((2x+5)*2)
We calculate terms in parentheses: -((2x+5)*2), so:
(2x+5)*2
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
We get rid of parentheses
-4x-10
Back to the equation:
+(-4x-10)
We get rid of parentheses
2x/()-4x-10=0
We multiply all the terms by the denominator
2x-4x*()-10*()=0
We add all the numbers together, and all the variables
2x-4x*()=0

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