(2x+4)/2=(9x-3)/3

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Solution for (2x+4)/2=(9x-3)/3 equation:



(2x+4)/2=(9x-3)/3
We move all terms to the left:
(2x+4)/2-((9x-3)/3)=0
We calculate fractions
2x/()+(-((9x-3)*2)/()=0
We calculate terms in parentheses: +(-((9x-3)*2)/(), so:
-((9x-3)*2)/(
We multiply all the terms by the denominator
-((9x-3)*2)
We calculate terms in parentheses: -((9x-3)*2), so:
(9x-3)*2
We multiply parentheses
18x-6
Back to the equation:
-(18x-6)
We get rid of parentheses
-18x+6
Back to the equation:
+(-18x+6)
We get rid of parentheses
2x/()-18x+6=0
We multiply all the terms by the denominator
2x-18x*()+6*()=0
We add all the numbers together, and all the variables
2x-18x*()=0

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