(2x+4)/4=(5x-10)/5

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Solution for (2x+4)/4=(5x-10)/5 equation: 



(2x+4)/4=(5x-10)/5

We move all terms to the left:

(2x+4)/4-((5x-10)/5)=0

We calculate fractions


2x/()+(-((5x-10)*4)/()=0



We calculate terms in parentheses: +(-((5x-10)*4)/(), so:

-((5x-10)*4)/(

We multiply all the terms by the denominator


-((5x-10)*4)



We calculate terms in parentheses: -((5x-10)*4), so:

(5x-10)*4

We multiply parentheses

20x-40

Back to the equation:

-(20x-40)



We get rid of parentheses

-20x+40

Back to the equation:

+(-20x+40)



We get rid of parentheses

2x/()-20x+40=0

We multiply all the terms by the denominator


2x-20x*()+40*()=0

We add all the numbers together, and all the variables

2x-20x*()=0

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