(2x+4)2x+4=256

Solution for (2x+4)2x+4=256 equation:

(2x+4)2x+4=256

We move all terms to the left:

(2x+4)2x+4-(256)=0

We add all the numbers together, and all the variables

(2x+4)2x-252=0

We multiply parentheses

4x^2+8x-252=0

a = 4; b = 8; c = -252;
Δ = b2-4ac
Δ = 82-4·4·(-252)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-64}{2*4}=\frac{-72}{8}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+64}{2*4}=\frac{56}{8}
=7
$