(2x+40)=(10x-16)

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Solution for (2x+40)=(10x-16) equation: 



(2x+40)=(10x-16)

We move all terms to the left:

(2x+40)-((10x-16))=0

We get rid of parentheses

2x-((10x-16))+40=0



We calculate terms in parentheses: -((10x-16)), so:

(10x-16)

We get rid of parentheses

10x-16

Back to the equation:

-(10x-16)



We get rid of parentheses

2x-10x+16+40=0

We add all the numbers together, and all the variables

-8x+56=0

We move all terms containing x to the left, all other terms to the right

-8x=-56

x=-56/-8

x=+7

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