(2x+43)+(3x+12)=90

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Solution for (2x+43)+(3x+12)=90 equation: 



(2x+43)+(3x+12)=90

We move all terms to the left:

(2x+43)+(3x+12)-(90)=0

We get rid of parentheses

2x+3x+43+12-90=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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