(2x+43)=(2x-3)=120

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Solution for (2x+43)=(2x-3)=120 equation: 



(2x+43)=(2x-3)=120

We move all terms to the left:

(2x+43)-((2x-3))=0

We get rid of parentheses

2x-((2x-3))+43=0



We calculate terms in parentheses: -((2x-3)), so:

(2x-3)

We get rid of parentheses

2x-3

Back to the equation:

-(2x-3)



We get rid of parentheses

2x-2x+3+43=0

We add all the numbers together, and all the variables

46!=0

There is no solution for this equation

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