(2x+46)=(3x+42)

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Solution for (2x+46)=(3x+42) equation: 



(2x+46)=(3x+42)

We move all terms to the left:

(2x+46)-((3x+42))=0

We get rid of parentheses

2x-((3x+42))+46=0



We calculate terms in parentheses: -((3x+42)), so:

(3x+42)

We get rid of parentheses

3x+42

Back to the equation:

-(3x+42)



We get rid of parentheses

2x-3x-42+46=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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