(2x+4x)/22=72

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Solution for (2x+4x)/22=72 equation: 


x in (-oo:+oo)

(2*x+4*x)/22 = 72 // - 72

(2*x+4*x)/22-72 = 0

(6*x)/22-72 = 0

(6*x)/22+(-72*22)/22 = 0

6*x-72*22 = 0

6*x-1584 = 0

(6*x-1584)/22 = 0

(6*x-1584)/22 = 0 // * 22

6*x-1584 = 0

6*x-1584 = 0 // + 1584

6*x = 1584 // : 6

x = 1584/6

x = 264

x = 264

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