(2x+4y)(2x-4y)=

Solution for (2x+4y)(2x-4y)= equation:

Simplifying
(2x + 4y)(2x + -4y) = 0

Multiply (2x + 4y) * (2x + -4y)
(2x * (2x + -4y) + 4y * (2x + -4y)) = 0
((2x * 2x + -4y * 2x) + 4y * (2x + -4y)) = 0

Reorder the terms:
((-8xy + 4x2) + 4y * (2x + -4y)) = 0
((-8xy + 4x2) + 4y * (2x + -4y)) = 0
(-8xy + 4x2 + (2x * 4y + -4y * 4y)) = 0
(-8xy + 4x2 + (8xy + -16y2)) = 0

Reorder the terms:
(-8xy + 8xy + 4x2 + -16y2) = 0

Combine like terms: -8xy + 8xy = 0
(0 + 4x2 + -16y2) = 0
(4x2 + -16y2) = 0

Solving
4x2 + -16y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16y2' to each side of the equation.
4x2 + -16y2 + 16y2 = 0 + 16y2

Combine like terms: -16y2 + 16y2 = 0
4x2 + 0 = 0 + 16y2
4x2 = 0 + 16y2
Remove the zero:
4x2 = 16y2

Divide each side by '4'.
x2 = 4y2

Simplifying
x2 = 4y2

Take the square root of each side:
x = {-2y, 2y}