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(2x+5)(-3x+4)=0
We multiply parentheses ..
(-6x^2+8x-15x+20)=0
We get rid of parentheses
-6x^2+8x-15x+20=0
We add all the numbers together, and all the variables
-6x^2-7x+20=0
a = -6; b = -7; c = +20;
Δ = b2-4ac
Δ = -72-4·(-6)·20
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-23}{2*-6}=\frac{-16}{-12} =1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+23}{2*-6}=\frac{30}{-12} =-2+1/2 $
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