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(2x+5)(2x+5)=49
We move all terms to the left:
(2x+5)(2x+5)-(49)=0
We multiply parentheses ..
(+4x^2+10x+10x+25)-49=0
We get rid of parentheses
4x^2+10x+10x+25-49=0
We add all the numbers together, and all the variables
4x^2+20x-24=0
a = 4; b = 20; c = -24;
Δ = b2-4ac
Δ = 202-4·4·(-24)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*4}=\frac{-48}{8} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*4}=\frac{8}{8} =1 $
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