(2x+5)(2x-4)x=15

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Solution for (2x+5)(2x-4)x=15 equation: 



(2x+5)(2x-4)x=15

We move all terms to the left:

(2x+5)(2x-4)x-(15)=0

We multiply parentheses ..

(+4x^2-8x+10x-20)x-15=0

We multiply parentheses

4x^3-8x^2+10x^2-20x-15=0

We do not support expression: x^3

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