(2x+5)(3x-12)(3x+11)=180

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Solution for (2x+5)(3x-12)(3x+11)=180 equation: 



(2x+5)(3x-12)(3x+11)=180

We move all terms to the left:

(2x+5)(3x-12)(3x+11)-(180)=0

We multiply parentheses ..

(+6x^2-24x+15x-60)(3x+11)-180=0

We move all terms containing x to the left, all other terms to the right

(+6x^2-24x+15x-60)(3x+11)=180

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