(2x+5)(3x-6=)

Solution for (2x+5)(3x-6=) equation:

(2x+5)(3x-6=)

We move all terms to the left:

(2x+5)(3x-6-())=0


We calculate terms in parentheses: +(2x+5)(3x-6-()), so:

2x+5)(3x-6-()

We add all the numbers together, and all the variables

2x+5)(3x

Back to the equation:

+(2x+5)(3x)


We multiply parentheses

6x^2+15x=0

a = 6; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·6·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*6}=\frac{-30}{12}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*6}=\frac{0}{12}
=0
$