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(2x+5)(4x+7)=0
We multiply parentheses ..
(+8x^2+14x+20x+35)=0
We get rid of parentheses
8x^2+14x+20x+35=0
We add all the numbers together, and all the variables
8x^2+34x+35=0
a = 8; b = 34; c = +35;
Δ = b2-4ac
Δ = 342-4·8·35
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-6}{2*8}=\frac{-40}{16} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+6}{2*8}=\frac{-28}{16} =-1+3/4 $
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