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(2x+5)(5x+4)=0
We multiply parentheses ..
(+10x^2+8x+25x+20)=0
We get rid of parentheses
10x^2+8x+25x+20=0
We add all the numbers together, and all the variables
10x^2+33x+20=0
a = 10; b = 33; c = +20;
Δ = b2-4ac
Δ = 332-4·10·20
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-17}{2*10}=\frac{-50}{20} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+17}{2*10}=\frac{-16}{20} =-4/5 $
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