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(2x+5)(6x+2)=0
We multiply parentheses ..
(+12x^2+4x+30x+10)=0
We get rid of parentheses
12x^2+4x+30x+10=0
We add all the numbers together, and all the variables
12x^2+34x+10=0
a = 12; b = 34; c = +10;
Δ = b2-4ac
Δ = 342-4·12·10
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-26}{2*12}=\frac{-60}{24} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+26}{2*12}=\frac{-8}{24} =-1/3 $
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